From 4ac32b3af9cc5bb8f29ba2ec20c89567eba752a2 Mon Sep 17 00:00:00 2001
From: Jan Aalmoes <jan.aalmoes@inria.fr>
Date: Tue, 26 Nov 2024 13:44:45 +0100
Subject: added tikz

---
 tikz/chaussette/a.tex | 30 +++++++++++++++---------------
 1 file changed, 15 insertions(+), 15 deletions(-)

(limited to 'tikz/chaussette/a.tex')

diff --git a/tikz/chaussette/a.tex b/tikz/chaussette/a.tex
index 1d001c2..595d196 100644
--- a/tikz/chaussette/a.tex
+++ b/tikz/chaussette/a.tex
@@ -1,33 +1,33 @@
 
 \begin{tikzpicture}
 \def \h{4}
-\node () at (0,1) {$X=0$};
+\node () at (0,1) {$Y=0$};
 \node[rectangle,draw=bonus] (G0) at (0,0) {$\begin{matrix}\bigcirc&\bigcirc\\\bigcirc&\bigcirc\end{matrix}$};
-\node () at (\h,1) {$X=1$};
+\node () at (\h,1) {$Y=1$};
 \node[rectangle,draw=bonus] (G1) at (\h,0){$\begin{matrix}\bigcirc&\bigcirc&\bigtriangleup\\&\bigcirc&\bigtriangleup\end{matrix}$};
-\node () at (2*\h,1) {$X=2$};
+\node () at (2*\h,1) {$Y=2$};
 \node[rectangle,draw=bonus] (G2) at (2*\h,0){$\begin{matrix}\bigcirc&\bigcirc&\times\\&\bigcirc&\times\end{matrix}$};
     \pause
 
         \node (L0) at (0,-2) {$
         \begin{matrix}
-            P(Y=\bigcirc|X=\emph{0}) = 1\\[6pt]
-            P(Y=\bigtriangleup|X=\emph{0}) = 0\\[6pt]
-            P(Y=\times|X=\emph{0}) = 0
+            P(S=\bigcirc|Y=\emph{0}) = 1\\[6pt]
+            P(S=\bigtriangleup|Y=\emph{0}) = 0\\[6pt]
+            P(S=\times|Y=\emph{0}) = 0
         \end{matrix}
         $};
         \node (L1) at (\h,-2) {$
         \begin{matrix}
-            P(Y=\bigcirc|X=\emph{1}) = \frac{3}{5}\\[6pt]
-            P(Y=\bigtriangleup|X=\emph{1}) = \frac{2}{5}\\[6pt]
-            P(Y=\times|X=\emph{1}) = 0
+            P(S=\bigcirc|Y=\emph{1}) = \frac{3}{5}\\[6pt]
+            P(S=\bigtriangleup|Y=\emph{1}) = \frac{2}{5}\\[6pt]
+            P(S=\times|Y=\emph{1}) = 0
         \end{matrix}
         $};
         \node (L2) at (2*\h,-2) {$
         \begin{matrix}
-            P(Y=\bigcirc|X=\emph{2}) = \frac{3}{5}\\[6pt]
-            P(Y=\bigtriangleup|X=\emph{2}) =0 \\[6pt]
-            P(Y=\times|X=\emph{2}) = \frac{2}{5}
+            P(S=\bigcirc|Y=\emph{2}) = \frac{3}{5}\\[6pt]
+            P(S=\bigtriangleup|Y=\emph{2}) =0 \\[6pt]
+            P(S=\times|Y=\emph{2}) = \frac{2}{5}
         \end{matrix}
         $};
 
@@ -47,9 +47,9 @@
 \pause
     \node (x2) at (2*\h,-3) {};
 
-    \node (f0) at (0,-4) {$f(\emph{0}) = \bigcirc$};
-    \node (f1) at (\h,-4) {$f(\emph{1}) = \bigcirc$};
-    \node (f2) at (2*\h,-4) {$f(\emph{2}) = \bigcirc$};
+    \node (f0) at (0,-4) {$a(\emph{0}) = \bigcirc$};
+    \node (f1) at (\h,-4) {$a(\emph{1}) = \bigcirc$};
+    \node (f2) at (2*\h,-4) {$a(\emph{2}) = \bigcirc$};
 
     \draw[->] (x0) to (f0);
     \draw[->] (x1) to (f1);
-- 
cgit v1.2.3

